Calcium carbonate, CaCO3, when heated decomposes to calcium oxide and carbon dioxide. Calulate the mass of clacium oxide formed when 2.0 grams of CaCO3 is decomposed.

CaCO3 ==> CaO + CO2

mols CaCO3 = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols CaCO3 to mols CaO. That's 1:1 so mols CaCO3 = mols CaO.
Then g CaO = mols CaO x molar mass CaO.

To calculate the mass of calcium oxide formed during the decomposition of calcium carbonate (CaCO3), we need to determine the molar ratio between calcium carbonate and calcium oxide.

Looking at the balanced chemical equation:
CaCO3(s) → CaO(s) + CO2(g)

From this equation, we can see that one mole of calcium carbonate decomposes to produce one mole of calcium oxide.

To calculate the molar mass of calcium carbonate:
- Calcium (Ca) has a molar mass of 40.08 g/mol
- Carbon (C) has a molar mass of 12.01 g/mol
- Oxygen (O) has a molar mass of 16.00 g/mol

Adding up the molar masses:
40.08 g/mol (Ca) + 12.01 g/mol (C) + 3 * 16.00 g/mol (O) = 100.09 g/mol (CaCO3)

Since the molar ratio between CaCO3 and CaO is 1:1, the molar mass of calcium oxide (CaO) is also 56.08 g/mol.

Using the calculated molar mass of calcium oxide, we can now determine the mass of calcium oxide formed when 2.0 grams of CaCO3 decomposes.

Mass of CaO = (2.0 g CaCO3) * (1 mol CaO / 100.09 g CaCO3) * (56.08 g CaO / 1 mol CaO)
Mass of CaO = 1.107 g

Therefore, 2.0 grams of CaCO3 decomposed produces approximately 1.107 grams of calcium oxide.