Given: 3H2(g) + N2(g) 2NH3(g)

If the reaction starts with 0.500 mol of H2, how many atoms of hydrogen in the compound NH3 would you expect to make?

To find the number of atoms of hydrogen in the compound NH3, we can use the given balanced chemical equation:

3H2(g) + N2(g) -> 2NH3(g)

From the balanced equation, we can see that for every 3 moles of H2, we produce 2 moles of NH3.

Given that the reaction starts with 0.500 mol of H2, we can use stoichiometry to find the number of moles of NH3 produced.

0.500 mol H2 * (2 mol NH3 / 3 mol H2) = 0.333 mol NH3

Next, we can use Avogadro's number (6.022 × 10^23) to convert the moles of NH3 into the number of atoms of hydrogen.

0.333 mol NH3 * (6.022 × 10^23 atoms / 1 mol) = 2.004 × 10^23 atoms of hydrogen

Therefore, you would expect to make approximately 2.004 × 10^23 atoms of hydrogen in the compound NH3.

To determine the number of atoms of hydrogen in the compound NH3, you need to first find out how many moles of NH3 are produced from 0.500 moles of H2.

The balanced equation tells us that the ratio between the moles of H2 and NH3 is 3:2. This means that for every 3 moles of H2, 2 moles of NH3 are produced.

To calculate the number of moles of NH3 produced, you can use the ratio from the balanced equation:

0.500 mol H2 * (2 mol NH3 / 3 mol H2) = 0.333 mol NH3

Now that you have the number of moles of NH3 produced, you can use Avogadro's number to calculate the number of atoms of hydrogen:

0.333 mol NH3 * (6.022 x 10^23 atoms/mol) = 2.00 x 10^23 atoms of hydrogen in NH3

Therefore, you would expect to produce 2.00 x 10^23 atoms of hydrogen in the compound NH3.

1. You don't have an arrow but I assume it goes between N2 and 2NH3.

2. You have no Kp or Kc listed.

3. You won't make any hydrogen atoms. Perhaps you meant, "How many atoms of hydrogen will be in the NH3 formed."