e^(ln(7)+2ln(4))−log9(27/27) the log has a base of 9 and the top 27 is under a radical sign.. my computer doesn't have symbols for them. the base of e is raised to In(7)+2In(4)
= e^(ln7+ln16) = e^ln112 = 112 √27/27 = 1/√27 = 27^(-1/2) = (9^3)^(-1/2) = 9^(-3/2) log_9(9^-3/2) = -3/2 remember that log_b(b^n) = n b^log_b(n) = n that is the definition of the log.
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