a flower pot is dropped out a twentieth story window. how fast will it be moving after 7 seconds? how much is the acceleration 3 seconds after it falls?
v(t)=g*t
after 3 seconds, or whenever, the acceleration is 9.8m/s^2
when an object is in free fall the acceleration (on earth) is alway 9.8m/s^2 [down]
To determine how fast the flower pot will be moving after 7 seconds, we need to use the equations of motion. Assuming no air resistance, we can use the equation:
v = u + at
where:
v is the final velocity,
u is the initial velocity (which is 0 since the flower pot was dropped),
a is the acceleration due to gravity (-9.8 m/s^2),
t is the time.
Substituting the values into the equation, we have:
v = 0 + (-9.8 m/s^2) * 7 s
v = -68.6 m/s
The negative sign shows that the flower pot is moving downwards.
To calculate the acceleration 3 seconds after it falls, we can use the equation:
a = (v - u) / t
where:
a is the acceleration,
v is the final velocity (which we can find using the equation above),
u is the initial velocity (which is 0 since the flower pot was dropped),
t is the time.
Substituting the values into the equation, we have:
a = (v - u) / t
a = (-68.6 m/s - 0 m/s) / 3 s
a = -22.87 m/s^2
Again, the negative sign indicates that the acceleration is towards the ground.
To calculate the speed of the flower pot after 7 seconds and the acceleration 3 seconds after it falls, we need to use the equations of motion under constant acceleration.
First, we need to determine the acceleration due to gravity. On Earth, acceleration due to gravity is approximately 9.8 m/s².
1. Speed after 7 seconds:
The equation to calculate the speed is:
v = u + at
v = final velocity
u = initial velocity (which is 0 in this case, as the flower pot is dropped and not given an initial velocity)
t = time taken
Since the flower pot is dropped, the initial velocity is 0. We'll assume the positive direction is downwards, so acceleration due to gravity is positive:
v = 0 + (9.8 m/s²) * 7 s
v = 68.6 m/s
Therefore, after 7 seconds, the flower pot will be moving approximately 68.6 meters per second.
2. Acceleration after 3 seconds:
The equation to calculate acceleration is:
a = (v - u) / t
a = acceleration
v = final velocity (which we know is 0, as the flower pot stops at the ground)
u = initial velocity (0 in this case)
t = time taken
Since the final velocity (v) of the flower pot after hitting the ground is 0, and it starts at rest (u = 0), we have:
a = (0 - 0) / 3 s
a = 0 / 3
a = 0 m/s²
Therefore, 3 seconds after it falls, the flower pot's acceleration will be 0 m/s².