Find the y-intercept of the tangent line to y= -0.2/sqrt(6+5x) at(2.5,-0.04990597277) Thanks
y = -0.2/√(6+5x)
y' = 0.5/√(6+5x)
y'(2.5) = 0.5/√18.5 ≈ 0.116
So, now you have a point and a slope. The line is thus
y+0.0499 = 0.116(x-2.5)
sub in x=0 to find the y-intercept.