Use the molar volume of a gas at STP to determine the volume (in L) occupied by 10.5g of neon at STP.
1 mol of Ne has a mass of 20.18 g and occupies a volume of 22.4 L at STP.
im not sure how to approach the problem i got 11.6 L
That's right.
10.5 g x (1 mol/20.18 g) = 0.5208 mols.
0.5208 mols x (22.4 L/mol) = 11.65 L which to 3 places is 11.6 L so you got right.
thank you!
To determine the volume occupied by 10.5g of neon at STP using the molar volume of a gas, we need to follow these steps:
Step 1: Determine the molar mass of neon (Ne).
The molar mass of neon (Ne) is the sum of the atomic masses of its constituents, which can be found on the periodic table.
Molar mass of neon (Ne) = 20.1797 g/mol
Step 2: Calculate the number of moles of neon.
We can use the formula n = m/M, where n is the number of moles, m is the mass, and M is the molar mass.
Number of moles of neon = 10.5g / 20.1797 g/mol
Step 3: Use the molar volume of a gas at STP to calculate the volume.
The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol.
Volume of neon = Number of moles of neon * Molar volume at STP
Volume of neon = (10.5g / 20.1797 g/mol) * 22.4 L/mol
Calculating this yields the volume occupied by 10.5g of neon at STP.