A waterfall is 1260m high. calculate the change in temperature of the quantity of water that falls from the top to the bottom of the waterfall( neglect heat losses to the surrounding) take g to be 10m/s and specific.heat capacity of water to be 4200j/kg/k.
mgh = mc▲t
cancel 'm' on both sides
gh = c▲t
10*1260 = 4200*▲t
(10*12600) / 4200 = ▲t
3 K = ▲t
What????
Put down the pipe and walk away from the classroom...
i have not seen the answer
To calculate the change in temperature of the water as it falls from the top to the bottom of the waterfall, we need to use the equation:
ΔT = (m * g * h) / (c * m)
Where:
ΔT = Change in temperature
m = Mass of water
g = Acceleration due to gravity (10 m/s^2)
h = Height of the waterfall (1260 m)
c = Specific heat capacity of water (4200 J/kg/K)
However, we need to know the mass of water in order to complete the calculation. We can calculate the mass using the equation:
m = d * V
Where:
m = Mass of water
d = Density of water (approximately 1000 kg/m^3)
V = Volume of water
To find the volume of water, we can use the equation:
V = A * h
Where:
V = Volume of water
A = Area of the waterfall (assuming it is constant throughout)
Since the dimensions of the waterfall are not given, it is difficult to determine the exact area. If you provide the necessary dimensions, I can continue with the calculations.