I thought I was getting the hang of these but I'm stumped on this one too. Any advise on how to solve it?
s e e d
+ i c e d
----------
s p i c e
c= ___ d=___ e=___ i= ___ p= ___ s=___
Hint: Solve for s and i. Then is e is even or odd?
Thanks.
Well, s has to be one, and to get a carry digit i has to be 8 or 9. e has to be even.
So e is 2,4,6,8
If e is 2, then c is 4 and i is six, wont work
if e is 4, c is 8, i is 2, wont work
if e is 6, c is 2, i is 8 works, but then s+i with carry wont be enough
if e is 8, c is 6, i is 5, works. Solved.
I thought i has to be 8 or 9 to get the carry over s=1. Wouldn't p=0?
who are you
tut no lig envo sup ojjh
To solve this problem, let's start by finding the values of the letters 's' and 'i'.
In the ones place, we have 'd' + 'e' = 'e'. Since 'e' is a single-digit number, this tells us that there is no carrying from the tens place. Therefore, 'd' + 'e' must be greater than or equal to 10. Since we are adding 'd' and 'e', which are both digits less than 10, the minimum sum is 0 + 1 = 1. This means that 'e' must be equal to or greater than 1.
Now, let's look at the equation for the tens place. We have 'c' + 'i' + 1 = 'p'. Rearranging this equation, we get 'c' + 'i' = 'p' - 1. Since 'p' is a single-digit number, 'p' - 1 is also a single-digit number. This means that there is no carrying from the hundreds place. Therefore, 'c' + 'i' must be less than 10.
Using the hint, let's consider the possible values for 's' and 'i'. Since 'e' is equal to or greater than 1, the maximum value for 's' and 'i' is 9. Now, let's try different values for 's' and 'i' and see if we find a satisfying solution.
If we let 's' be 9 and 'i' be 1, then 'c' + 1 = 0. Since 'c' is a digit less than 10, this equation does not have a solution.
If we let 's' be 8 and 'i' be 2, then 'c' + 2 = 1. Again, this equation does not have a solution.
If we continue this process, we find that there is no satisfying solution for 's' and 'i' where both values are less than or equal to 9.
Now let's consider the case where 's' and 'i' are double-digit numbers. If we let 's' be 23 and 'i' be 91, then 'c' + 91 = 13. Solving for 'c', we get 'c' = -78. However, 'c' must be a digit less than 10, so this solution does not work either.
Based on our deductions so far, we can conclude that there is no satisfying solution for 's' and 'i' for this equation.
Regarding 'e', since we haven't found a solution for 's' and 'i', we cannot determine whether 'e' is even or odd in this case.
Therefore, there is no solution to this particular equation.