Is anybody smarter than a fifth grader on this problem? I'm not able to help my son with this homework problem.
e g g
+ e g g
---------
p a g e
a=____ e=____ g=____ p=_1___
How we started: p = 1, and g is greater than 5.
Thanks!
http://www.kidzone.ws/math/eggplusegg/index.htm
Thanks very much! You're going to make me a hero with my son.
-Rich
To solve this problem, we need to find the values of the letters a, e, g, and p that satisfy the given equation.
1. Start with the given information: p = 1 and g is greater than 5.
2. Let's go step by step and try to find the values of other letters.
3. Let's consider the column where the letter "g" appears. Since g is greater than 5, it cannot be 0. Therefore, it must be either 6, 7, 8, or 9.
4. Now, let's move to the column where the letter "e" appears. We know that e + g = g, which means e + g must have a carry-over to the next column, where the letter "a" appears. We can see that g + g = p (since there is no carry-over from the "e + g" addition). Therefore, the only possible value for g is 9 (since it has to be greater than 5), which means e + 9 = 9. Hence, e must be 0.
5. Now that we know g is 9 and e is 0, we can go back to the first column where the letter "a" appears. Since a + g = e, we have a + 9 = 0. Therefore, a must be -9.
6. Finally, we can substitute the values we found into the original equation: -9 0 9 + 0 9 9 = 1 0 9 9. The equation is now balanced.
To summarize the solution:
a = -9
e = 0
g = 9
p = 1
So, nobody is necessarily "smarter" than a fifth grader on this problem, as it involves basic addition and logical deduction.