the current in alightning strike is 7500A.the strike lasts for 240ms.calculate
a,the charge in c ,which flows in the strike to the ground
b,the number of electrons transferred to the ground
To calculate the charge that flows in the lightning strike to the ground, we can use the equation:
Charge (C) = Current (A) × Time (s)
Given that the current in the lightning strike is 7500A and the strike lasts for 240ms (0.24s), we can substitute these values into the equation to find the charge:
a) Charge (C) = 7500A × 0.24s
Charge (C) = 1800 Coulombs (C)
Therefore, the charge that flows in the lightning strike to the ground is 1800C.
To calculate the number of electrons transferred to the ground, we need to know the charge of a single electron and divide the total charge by that value.
The charge of a single electron is approximately 1.6 × 10^(-19) C.
b) Number of Electrons = Charge (C) / Charge of a Single Electron
Number of Electrons = 1800C / (1.6 × 10^(-19) C)
Using the above equation, we can calculate the number of electrons transferred to the ground:
Number of Electrons ≈ 1.13 × 10^38 electrons
Therefore, approximately 1.13 × 10^38 electrons are transferred to the ground during the lightning strike.
An amp is 1C/1s
so it = Q (that's current times time, not "it" the word)
for part b take the Q you found and divide by elemental charge 1.6e-19