Calculate the amount of heat energy transferred in the following situations:
the temperature of 1.0g water rises from 22.5 degrees C to 24.5 degrees C.
Feel like I am missing givens. Help! There are a few more like this but I just need to know how to set it up.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
You are looking for q. mass is given, you need to look up specific heat H2O (4.184 J/g*C) and you have Tfinal and Tinitial. Solve for q.
To calculate the amount of heat energy transferred, you need to use the heat capacity formula:
q = m * c * ΔT
where:
q is the amount of heat energy transferred (in Joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
In this case, you have the mass of water (1.0 g) and the change in temperature (ΔT = 24.5°C - 22.5°C = 2.0°C). However, you need to know the specific heat capacity of water to proceed.
The specific heat capacity of water is approximately 4.18 J/g°C. Using this value, you can calculate the amount of heat energy transferred:
q = 1.0 g * 4.18 J/g°C * 2.0°C
q = 8.36 Joules
Therefore, in this situation, the amount of heat energy transferred is 8.36 Joules.