22 moles of benzene are completely reacted with molecular oxygen, how many moles of carbon dioxide will be produced? and if 150 grams of water were produced, how many moles of oxygen must have reacted
2C6H6 + 15O2 ==> 12CO2 + 6H2O
22 mols C6H6 x (12 mols CO2/2 mols C6H6) = 22 x 12/2 = ?
mols H2O = grams/molar mass = ?
Then ?mols H2O x (12 mols O2/6 mols H2O) = ? mols H2O x 12/6 = xx
Benzene is C6H6
a. If 22.0 mol of benzene are completely reacted with molecular oxygen, how many
moles of CO2 will be produced?
b. If 150 g of water are produced, how many moles of oxygen must have reacted?
To determine the number of moles of carbon dioxide produced when 22 moles of benzene react with molecular oxygen, we need to first identify the balanced chemical equation for the reaction.
The balanced equation for the combustion of benzene is:
C6H6 + 15O2 -> 6CO2 + 3H2O
From the equation, we can see that for every mole of benzene (C6H6) that reacts, 6 moles of carbon dioxide (CO2) are produced.
Therefore, if 22 moles of benzene react, we can calculate the moles of carbon dioxide produced using the following ratio:
22 moles benzene x (6 moles CO2 / 1 mole benzene) = 132 moles carbon dioxide
So, 22 moles of benzene would produce 132 moles of carbon dioxide.
Now, let's move on to the second part of the question. If 150 grams of water were produced, we need to calculate the number of moles of oxygen that must have reacted.
First, we need to determine the number of moles of water produced. The molar mass of water (H2O) is approximately 18 grams/mole (2 hydrogen atoms with a molar mass of 1 gram/mole each and 1 oxygen atom with a molar mass of 16 grams/mole).
Number of moles of water = Mass of water / Molar mass of water
Number of moles of water = 150 grams / 18 grams/mole ≈ 8.33 moles
From the balanced equation, we can see that for every 3 moles of water (H2O) produced, 15 moles of oxygen (O2) are consumed.
Therefore, we can calculate the number of moles of oxygen consumed using the following ratio:
8.33 moles water x (15 moles O2 / 3 moles water) = 41.65 moles oxygen
So, approximately 41.65 moles of oxygen must have reacted to produce 150 grams of water.