Figure ABCD has vertices A(−4, 1), B(2, 1), C(2, −5), and D(−4, −3). What is the area of Figure ABCD?

24 square units
30 square units
36 square units
45 square units

is it C?

Did you plot the points?

Look like a trapezoid.
AB is a horizontal line, so that AB = 6
AC and BC are parallel
So area = (1/2(AC + BC)(AB)
= (1/2)(4+6)(6) = 30 square units

hey I need help with the same thing too weres the teachers? I wish they can come and help

To find the area of figure ABCD, you can use the formula for the area of a rectangle. However, note that the word "rectangle" is not mentioned in the question, but since all sides are parallel, it can be assumed that it is a rectangle.

The formula for the area of a rectangle is: Area = length × width.

To calculate the length and width of the rectangle, you can use the coordinates of its vertices.

The length of the rectangle can be found by calculating the difference between the x-coordinates of points A and B. In this case, it is -4 - 2 = -6 units.

The width of the rectangle can be found by calculating the difference between the y-coordinates of points B and C. In this case, it is -5 - 1 = -6 units.

Now, plug in the values into the area formula: Area = (-6) × (-6) = 36 square units.

So, the correct answer is C, 36 square units.

I don't know but I need help asap