A bag contains 4 white, 3 blue, and 5 red marbles.
1. Find the probability of choosing a blue marble, then a red marble if the marbles are not replaced.
a. 5/44
b. 15/35
c. 2/3 (i pick this)
2. 1/15
2. Find the probability of choosing two white marbles in a row.
a. 1/11
b. 1/9 (i pick this)
c. 2/3
d. 1/16
1) C
2) B
4+3+5=12
3/12 (simplify) 1/4
4/12 (simplify) 1/3
I hope this helped :-/
It was 1. A
2. A
To find the probability of selecting two events in a row, you multiply the probabilities of each event happening. Let's solve each question step by step:
1. Find the probability of choosing a blue marble, then a red marble if the marbles are not replaced:
First, let's find the probability of choosing a blue marble. There are 3 blue marbles out of a total of 12 marbles (4 white + 3 blue + 5 red). So the probability of choosing a blue marble is 3/12.
Now, since we are not replacing the marble, there will be one less marble in the bag for the second event. Therefore, there will be a total of 11 marbles left. Out of these 11, 5 are red marbles. So the probability of choosing a red marble in the second event is 5/11.
To find the overall probability, we multiply the probabilities of each event happening: (3/12) * (5/11) = 15/132 = 5/44.
Therefore, the correct answer is a. 5/44.
2. Find the probability of choosing two white marbles in a row:
Similarly, we first find the probability of choosing a white marble. There are 4 white marbles out of a total of 12 marbles. So the probability of choosing a white marble is 4/12.
Since we are not replacing the marbles, for the second event, there will be one less marble in the bag. Therefore, there will be a total of 11 marbles left. And since we already chose one white marble, there will be 3 white marbles left. So the probability of choosing a second white marble is 3/11.
To find the overall probability, we multiply the probabilities of each event happening: (4/12) * (3/11) = 12/132 = 1/11.
Therefore, the correct answer is a. 1/11.