How much kinetic energy does a 0.03 kg bullet traveling at a speed of 300 m/s have?
1/2 mv^2
To find the kinetic energy of a moving object, you can use the formula:
Kinetic Energy (KE) = (1/2) * mass * velocity^2
In this case, the mass of the bullet is given as 0.03 kg, and the speed is 300 m/s.
Substituting these values into the formula, we have:
KE = (1/2) * 0.03 kg * (300 m/s)^2
First, let's calculate (300 m/s)^2:
(300 m/s)^2 = 300 * 300 = 90,000 m^2/s^2
Now, substitute this value back into the formula:
KE = (1/2) * 0.03 kg * 90,000 m^2/s^2
Next, multiply 0.03 kg by 90,000 m^2/s^2:
KE = 2,700 kg * m^2/s^2
Finally, simplify the units:
1 kg * m^2/s^2 = 1 Joule (J)
Therefore, the kinetic energy of the 0.03 kg bullet moving at a speed of 300 m/s is 2,700 Joules.