3. What are the solutions of the system?
y = x + 5
y = x^2 - x + 2
A. (3,14) and (-1,0)
B. (3,8) and (-1,4)
C. (3,8) and (-1,0)
D. (-3,2) and (1,6)
4. What are the solutions of the system?
y = x^2 - 2x - 8
y = x + 2
A. (5,7) and (-2,0)
B. (5,3) and (-2,4)
C. (-5,-3) and (2,4)
D. (5,3) and (2-4)
worst case, just try the possibilities. One will work.
Or, using substitution, note that
#3: y=x+5, so
x+5 = x^2-x+2
x^2=2x-3 = 0
...
#4: y=x+2, so
x+2 = x^2-2x-8
x^2-3x-10 = 0
...
Now it's just factoring.