Calculate the heat given off by the hot water.
GIVEN:
Original quantity of water (hot water) 50g
Orig.temperature :40°C
Final temperature: 9°C
Final quantity of water: 264g
Increase in quantity of water 214g.
PLEASE KINDLY SHOW ME THE EQUATION FOR THIS THANK YOU. <3
The equation for calculating the heat given off by the hot water can be found using the formula for specific heat capacity:
Q = mcΔT
Where:
Q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, the initial quantity of water is given as 50g and the final quantity is given as 264g. So, there is an increase in quantity of water by 214g.
To calculate the heat given off by the hot water, we need to find the change in temperature (ΔT) and the specific heat capacity of water (c). The specific heat capacity of water is approximately 4.18 J/g°C.
Step 1: Calculate the change in temperature (ΔT):
ΔT = Final temperature - Initial temperature
ΔT = 9°C - 40°C
ΔT = -31°C
Step 2: Calculate the heat energy (Q):
Q = mcΔT
Q = (mass of water) x (specific heat capacity of water) x (change in temperature)
Q = (264g) x (4.18 J/g°C) x (-31°C)
Q = -34321.92 J
Therefore, the heat given off by the hot water is approximately -34321.92 J. The negative sign indicates that heat is being lost by the hot water during the cooling process.
To calculate the heat given off by the hot water, we can use the equation:
Q = mcΔT
Where:
Q is the heat given off (in joules),
m is the mass of the water (in grams),
c is the specific heat capacity of water (which is approximately 4.18 J/g°C),
ΔT is the change in temperature (in °C).
First, let's calculate the initial mass of water:
Initial mass = Original quantity of water + Increase in quantity of water
Initial mass = 50g + 214g
Now, let's calculate the heat given off:
Q = m * c * ΔT
ΔT = Final temperature - Original temperature
ΔT = 9°C - 40°C
Substituting the values into the equation:
Q = (Initial mass) * c * ΔT
Q = (Initial mass) * 4.18 J/g°C * (9°C - 40°C)
Simplifying the equation and converting grams to kilograms:
Q = ((50g + 214g) / 1000kg/g) * 4.18 J/g°C * (-31°C)
Therefore, the equation to calculate the heat given off by the hot water is:
Q = ((50g + 214g) / 1000) * 4.18 * -31 Joules
You can then calculate the value of Q to find the heat given off by the hot water.