Calculate the heat given off by the hot water.
GIVEN:
Original quantity of water (hot water) 50g
Orig.temperature :40°C
Final temperature: 9°C
Final quantity of water: 264g
Increase in quantity of water 214g.
PLEASE KINDLY SHOW ME THE EQUATION FOR THIS THANK YOU. <3
I don't understand for certain. You give one orig temp, 40C. Is that the hot water?
heatgivenoff=50(cwater)(9-40) if 40C was the orig temp of hot water.
To calculate the heat given off by the hot water, you can use the specific heat capacity formula:
Q = mcΔT
Where:
Q is the heat given off or absorbed (in joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
Given:
Original quantity of water (hot water): m1 = 50g
Original temperature: T1 = 40°C
Final temperature: T2 = 9°C
Final quantity of water: m2 = 264g
Increase in quantity of water: Δm = 214g
To calculate the heat given off by the hot water, we need to find the change in temperature (ΔT), which is the difference between the final temperature and the initial temperature:
ΔT = T2 - T1
Next, we need to calculate the mass of the hot water after the change in quantity:
m2 = m1 + Δm
Now, we can substitute the values into the formula to calculate the heat given off:
Q = mcΔT
Q = m2c(ΔT)
In this case, we need to substitute m2 for m in the formula because the quantity of water has changed.
Finally, calculate the heat (Q) by multiplying the mass of the water after the change by the specific heat capacity and the change in temperature:
Q = m2c(ΔT)
Please note that you need to know the specific heat capacity of water (c) to complete the calculation, which is approximately 4.18 J/g°C.