Write the balanced equation for the neutralization reaction between H3PO4 and NaOH in aqueous solution. Phases are optional.
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To determine the balanced equation for the neutralization reaction between H3PO4 (phosphoric acid) and NaOH (sodium hydroxide) in aqueous solution, we need to consider their respective chemical formulas and react with each other.
First, let's write the chemical formulas for phosphoric acid and sodium hydroxide:
- H3PO4 represents 3 hydrogen atoms, 1 phosphorous atom, and 4 oxygen atoms.
- NaOH represents 1 sodium atom, 1 oxygen atom, and 1 hydrogen atom.
The balanced equation for this neutralization reaction can be determined by ensuring that the number of atoms on both sides of the equation is equal. To do so, we follow these steps:
Step 1: Write the chemical equation using the reactants and products.
H3PO4 + NaOH -> ?
Step 2: Identify the products formed when an acid (H3PO4) reacts with a base (NaOH).
The neutralization reaction between an acid and a base typically produces water (H2O) and a salt. In this case, the salt formed will depend on the acid and base used.
In the reaction between H3PO4 and NaOH, the salt formed will be sodium phosphate (Na3PO4).
So, the products are H2O and Na3PO4.
Step 3: Balance the equation by ensuring the number of atoms is the same on both sides.
H3PO4 + 3NaOH -> 3H2O + Na3PO4
Thus, the balanced equation for the neutralization reaction between H3PO4 and NaOH in aqueous solution is:
H3PO4 + 3NaOH -> 3H2O + Na3PO4