Calculate the volume of hydrogen produced at s.t.p when 25g of zinc are added to excess dilute hydrochloric at 3degree and 778mmhg pressure
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = grams/atomikc mass = ?
Using the coefficients in the balanced equation, convert mols Zn to mols H2. Since this is a 1:1 reaction, mols H2 = mols Zn.
Then use PV = nRT to solve for V at the conditions listed. Remember T must be in kelvin and P must be in atm. Atm = 778/760 = ?
Zn + 2HCl = ZnCl + HE
1mol. 1 mol
Zn = 25g÷ 65g= 0.3846mol
H2 × Vm = 0.3846 × 22.4
= 8.6150
~ 8.62