what is the oxidation number of Chlorine in KCIO4???

+7

K = +1
O = -2 and 4*-2 = -8
What must Cl be for KClO4 to be zero. Remember that all compounds or elements in the free state are zero total.
+1 + ? + (-8) = 0

To determine the oxidation number of chlorine (Cl) in the compound KClO4 (potassium perchlorate), we need to follow a set of rules:

1. The oxidation number of an element in its pure form is always zero. Therefore, the oxidation number of potassium (K) is 0.

2. The sum of the oxidation numbers of all the atoms in a compound must equal zero.

3. The oxidation number of oxygen (O) is typically -2, except when it is in a peroxide (O2^2-) ion, in which case it is -1.

With these rules in mind, we can proceed to find the oxidation number of chlorine (Cl) in KClO4:

Let the oxidation number of Cl be x.
Let the oxidation number of O be -2.

Since there are four oxygen atoms in KClO4, their total oxidation number is (4 x -2) = -8.

The sum of the oxidation numbers in the compound must be zero:

(K: 0) + (Cl: x) + (O: -8) = 0

Simplifying the equation, we have:

x - 8 = 0

Adding 8 to both sides of the equation:

x = 8

Therefore, the oxidation number of chlorine (Cl) in KCIO4 is +8.