What will be the volume of ammonia formed from 2L of nitrogen and 2L of hydrogen
"According to the equation, for 1 molecule of nitrogen (N2) gas and 3 molecules of hydrogen (H2) gas, 2 molecules of ammonia gas (NH3) are produced. So the mole ratio of Nitrogen to Ammonia is 1:2.
Assuming both Nitrogen gas and Ammonia gas are close approximations to an ideal gas, a mole of each occupies the same volume. So the volume ratio is the same as the mole ratio."
(Vammonia) / 4.74L = 2 / 1
So it's twice the volume.
Hope I helped you...
I disagree with Nerd. This is a limiting reagent (LR) problem.
N2 + 3H2 ==> 2NH3
a. Convert 2 L N2 to mols NH3 produced if we had all of the H2 needed. That is 2 L N2 x (2 mols NH3/1 mol N2) = 2 x 2 = 4 L NH3
b. Convert 2 L H2 to mols NH3 produced if we had all of the N2 needed. That is 2 L H2 x (2 mols NH3/3 mols H2) = 2 x 2/3 = 4/3 or 1-1/3 L NH3.
c. The two answers for L NH3 produced don't agree; in LR problems the SMALLER amount is ALWAYS the correct value to use and the reactant responsible for that value is the LR. So you will produce 1-1/3 L NH3, use up all of the H2 and you will have some N2 remaining after the reaction is complete. The amount of N2 remaining un-reacted can be calculated if you wanted to do that.
To calculate the volume of ammonia formed from the reaction between nitrogen (N2) and hydrogen (H2), you need to know the balanced chemical equation and the stoichiometry of the reaction.
The balanced chemical equation for the reaction is:
N2 + 3H2 -> 2NH3
This equation tells us that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
To calculate the volume of ammonia formed, follow these steps:
Step 1: Convert the given volumes of nitrogen and hydrogen to moles using the ideal gas law equation:
PV = nRT
Where:
P is the pressure (assumed constant)
V is the volume
n is the number of moles
R is the ideal gas constant
T is the temperature (assumed constant)
Since the pressure, temperature, and gas constant are assumed constant, the equation simplifies to:
V/n = constant
So, V₁/n₁ = V₂/n₂
Where V₁ and V₂ are the given volumes, and n₁ and n₂ are the moles of nitrogen and hydrogen, respectively.
Step 2: Use the stoichiometry of the balanced equation to determine the mole ratio between nitrogen and ammonia. From the equation, we can see that 1 mole of nitrogen produces 2 moles of ammonia.
Step 3: Calculate the moles of ammonia produced by multiplying the moles of nitrogen by the mole ratio obtained in step 2.
Step 4: Convert the moles of ammonia to volume using the ideal gas law equation:
V = nRT/P
Since the pressure, temperature, and gas constant are assumed constant, the equation simplifies to:
V = n * constant
Where V is the volume, n is the number of moles of ammonia obtained in step 3, and the constant includes the gas constant and other constants.
By following these steps, you should be able to calculate the volume of ammonia formed from the given volumes of nitrogen and hydrogen.