Calculate the mass in grams present in 0.95 mole of sodium hydrogen trioxocarbonate(iv)
So the molar mass of Na2(CO3) is 84g/mol..check that.
mass is .95 times the molar mass.
Why don't you use sodium hydrogen carbonate for the name.
Bob Pursley gave you the right procedure and the right numbers. That 84 should be for NaHCO3.
To calculate the mass in grams present in 0.95 moles of sodium hydrogen trioxocarbonate (IV), you need to know the molar mass of the compound.
The molar mass of sodium hydrogen trioxocarbonate (IV) can be calculated by summing the molar masses of its constituent elements. The compound consists of sodium (Na), hydrogen (H), carbon (C), and oxygen (O).
The atomic masses of these elements are as follows:
- Sodium (Na) - 22.99 g/mol
- Hydrogen (H) - 1.01 g/mol
- Carbon (C) - 12.01 g/mol
- Oxygen (O) - 16.00 g/mol
The formula for sodium hydrogen trioxocarbonate (IV) is NaHCO3.
To calculate the molar mass, you multiply the number of atoms of each element by their respective atomic masses, and then add them up:
NaHCO3: 1 Na + 1 H + 1 C + 3 O
= (1 * 22.99) + (1 * 1.01) + (1 * 12.01) + (3 * 16.00)
= 22.99 + 1.01 + 12.01 + 48.00
= 84.01 g/mol
Therefore, the molar mass of sodium hydrogen trioxocarbonate (IV) is 84.01 g/mol.
To calculate the mass in grams present in 0.95 moles of the compound, you can use the following formula:
Mass (g) = Molar mass (g/mol) * Number of moles
Mass (g) = 84.01 g/mol * 0.95 mol
= 79.81 grams
Therefore, the mass in grams present in 0.95 moles of sodium hydrogen trioxocarbonate (IV) is 79.81 grams.
To calculate the mass of a compound, you need to know its molar mass. The molar mass can be calculated by adding up the atomic masses of all the elements present in the compound.
In this case, the compound is sodium hydrogen trioxocarbonate(IV) with the chemical formula NaHCO3.
To calculate the molar mass, we need to know the atomic masses of the elements involved. The atomic mass of sodium (Na) is 22.99 g/mol, hydrogen (H) is 1.01 g/mol, carbon (C) is 12.01 g/mol, and oxygen (O) is 16.00 g/mol.
The molar mass of NaHCO3 can be calculated as follows:
(1 * Na) + (1 * H) + (1 * C) + (3 * O)
= (1 * 22.99) + (1 * 1.01) + (1 * 12.01) + (3 * 16.00)
= 22.99 + 1.01 + 12.01 + 48.00
= 84.01 g/mol
Now that you know the molar mass of NaHCO3 is 84.01 g/mol, you can calculate the mass in grams present in 0.95 moles of the compound.
mass (in grams) = molar mass * number of moles
= 84.01 g/mol * 0.95 mol
= 79.81 grams
Therefore, the mass present in 0.95 moles of sodium hydrogen trioxocarbonate(IV) is 79.81 grams.