The balanced reaction equation for the combustion of heptane, C7H16, is given below. If the reaction produced 37.5 g CO2, how many grams of heptane were burned?

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The balanced reaction equation for the combustion of heptane, C7H16, is as follows:

C7H16 + 11 O2 -> 7 CO2 + 8 H2O

From the equation, we can see that the stoichiometric ratio between heptane (C7H16) and carbon dioxide (CO2) is 1:7. That means for every 1 mole of C7H16 burned, 7 moles of CO2 are produced.

To find the number of moles of CO2 produced, we can use its molar mass. The molar mass of CO2 is 44.01 g/mol.

Given that 37.5 g of CO2 are produced, we can calculate the moles of CO2 produced:

moles of CO2 = mass of CO2 / molar mass of CO2
moles of CO2 = 37.5 g / 44.01 g/mol = 0.851 mol

Since the stoichiometric ratio between heptane and CO2 is 1:7, the number of moles of heptane burned is:

moles of C7H16 = moles of CO2 / 7 = 0.851 mol / 7 = 0.122 mol

Finally, to find the mass of heptane burned, we can use its molar mass, which is 100.21 g/mol:

mass of C7H16 = moles of C7H16 * molar mass of C7H16
mass of C7H16 = 0.122 mol * 100.21 g/mol = 12.26 g

Therefore, 12.26 grams of heptane were burned.

To find the number of grams of heptane burned, we need to use the balanced reaction equation and the stoichiometric ratios. The balanced reaction equation for the combustion of heptane is:

C7H16 + 11O2 -> 7CO2 + 8H2O

From the balanced equation, we can see that for every mole of heptane burned, 7 moles of CO2 are produced. We can use this ratio to find the number of moles of heptane burned.

First, find the molar mass of CO2. Carbon has a molar mass of 12.01 g/mol, and oxygen has a molar mass of 16.00 g/mol. Since CO2 has one carbon and two oxygen atoms, the molar mass of CO2 is:

Molar mass of CO2 = 12.01 g/mol + 2 * 16.00 g/mol
= 44.01 g/mol

Next, use the molar mass of CO2 to convert grams of CO2 to moles of CO2:

Number of moles of CO2 = Mass of CO2 / Molar mass of CO2
= 37.5 g / 44.01 g/mol

Now, use the stoichiometric ratio to find the number of moles of heptane burned:

Number of moles of heptane = Number of moles of CO2 * (1 mole of C7H16 / 7 moles of CO2)

Finally, use the molar mass of heptane to convert moles of heptane to grams of heptane:

Mass of heptane = Number of moles of heptane * Molar mass of C7H16

Plug in the values and calculate the answer:

Mass of heptane = (37.5 g / 44.01 g/mol) * (1 mole of C7H16 / 7 moles of CO2) * Molar mass of C7H16

Note: The molar mass of C7H16 can be calculated by adding up the atomic masses of its constituent elements.

C7H16 + 11O2 ==> 7CO2 + 8H2O

mols CO2 = grams/molar mass = 37.5/44 = approx 0.85

Convert mols CO2 to mols C7H16 using the coefficients in the balanced equation.
approx 0.85 x (1 mol C6H16/8 mols CO2) = approx 0.85 x 1/8 = 0.1 mol C7H16

g C7H16 = mols C7H16 x molar mass C7H16 = ? grams.

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