The sample space for a roll of two number cubes is shown in the table.
(1,1)|(1,2)|(1,3)|(1,4)|(1,5),(1,6)
(2,1)|(2,2)|(2,3)|(2,4)|(2,5)|(2,6)
(3,1)|(3,2)|(3,3)|(3,4)|(3,5)|(3,6)
(4,1)|(4,2)|(4,3)|(4,4)|(4,5)|(4,6)
(5,1)|(5,2)|(5,3)|(5,4)|(5,5)|(5,6)
(6,1)|(6,2)|(6,3)|(6,5)|(6,5)|(6,6)
What is the probability that the roll will result in one even and one odd number?
A. 1/9
B. 1/4
C. 1/3
D. 1/2 ***
The sample space for a roll of two number cubes is shown in the table.
(1,1)|(1,2)|(1,3)|(1,4)|(1,5),(1,6)
(2,1)|(2,2)|(2,3)|(2,4)|(2,5)|(2,6)
(3,1)|(3,2)|(3,3)|(3,4)|(3,5)|(3,6)
(4,1)|(4,2)|(4,3)|(4,4)|(4,5)|(4,6)
(5,1)|(5,2)|(5,3)|(5,4)|(5,5)|(5,6)
(6,1)|(6,2)|(6,3)|(6,5)|(6,5)|(6,6)
What is the probability that the roll will result in two odd numbers?
(A) 1/9
(B) 1/4
(C) 1/3
(D) 4/9
PLEASE PLEASE PLEASE HELP!!!
@NEED ANSWERS the answers are different for everyone lol so you just have to look up individual questions -w-
correct. The first roll is either even or odd.
So, the chance that the 2nd roll is odd (or even) is 1/2
@big U W U is correct. The tests are different for everybody.
Please correct me if I'm wrong.
I think its 1/4 or b. 9 of the 36 possibilities have TWO odd numbers, I believe if you dived 9/36 by 3 you end up with 3/12 and divide that by 3 causing it to be 1/4 or b.
That was for msm not this question
does any body have the answers tot he test
thanks guy!
To find the probability that the roll will result in one even and one odd number, we need to determine the number of favorable outcomes and the total number of possible outcomes.
In this case, the favorable outcomes are the pairs of numbers on the number cubes that consist of one even number and one odd number.
Looking at the table, we can see that there are 18 possible combinations of rolls:
(1,2), (1,4), (1,6)
(2,1), (2,3), (2,5)
(3,2), (3,4), (3,6)
(4,1), (4,3), (4,5)
(5,2), (5,4), (5,6)
(6,1), (6,3), (6,5)
Out of these 18 possible outcomes, there are 12 favorable outcomes where one number is odd and the other number is even.
Therefore, the probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes:
P(one even and one odd) = (number of favorable outcomes) / (total number of possible outcomes) = 12/18 = 2/3
So the correct answer is C. 1/3.