if a die is tossed four times what is the probability of getting anything but a five on every toss

To find the probability of getting anything but a five on every toss, we need to determine the number of successful outcomes (not getting a five) and divide it by the total number of possible outcomes.

First, let's determine the number of successful outcomes:
- On each toss, there are 5 possible outcomes (numbers 1, 2, 3, 4, and 6), except for the number 5.

Since we are tossing the die four times, the total number of successful outcomes would be:
5 × 5 × 5 × 5 = 625

Next, let's determine the total number of possible outcomes:
- On each toss, there are 6 possible outcomes (numbers 1, 2, 3, 4, 5, and 6).

Since we are tossing the die four times, the total number of possible outcomes would be:
6 × 6 × 6 × 6 = 1296

Now, we can calculate the probability:
Probability = Number of successful outcomes / Total number of possible outcomes

Probability = 625 / 1296 ≈ 0.4815

Therefore, the probability of getting anything but a five on every toss is approximately 0.4815 or 48.15%.