In triangle ABC , <C is a right angle. Find the remaining sides and angles. Round your answers to the nearest tenth. Show your work.
a = 3, c = 19
c^2= a^2+b^2
19^2 = 3^2+b^2
361= 9+b^2
b= √352 = 18.8
tanA= 3/18.8
A= arctan (3/18.8)
A= 9.1
tanB= 18.8/3
B= arctan (18.8/3)
B= 80.9
Is my work correct?
yes all 3 are correct
but it is easier to use sin and cos
sin^-1 (3/19) and cos^-1 (18.8/19)