The diagonals of rectangle ABCD intersect at point E. If AE=2x+5, and BD=5x+2, what is AC?

62

well, the diagonals have the same length, and bisect each other.

So, BD = 2*AE

Set up the equation, solve for x, and then AC = BD

BASE is a rectangle it's diagonals intersect at o find x if OB= 5x + 1 and OC =2x -14

Why always no answer...

To find the length of AC, we need to use the property of diagonals in a rectangle. In a rectangle, the diagonals are congruent, meaning they are equal in length.

Let's denote the length of AC as d. Since the diagonals of a rectangle are congruent, we can say that AE = CD and BE = AD.

From the given information, AE = 2x + 5 and BD = 5x + 2. We can set up an equation using these lengths:

2x + 5 = 5x + 2

Now, let's solve for x:

2x - 5x = 2 - 5
-3x = -3
x = 1

Now that we have the value of x, we can substitute it back into the equation to find the length of AC:

AC = CD = AE = 2x + 5 = 2(1) + 5 = 2 + 5 = 7

Therefore, the length of AC is 7.