Water flows over a section of Niagara Falls at

the rate of 1.3 × 106
kg/s and falls 49.8 m.
How much power is generated by the
falling water? The acceleration of gravity
if 9.81 m/s^2.

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To calculate the power generated by the falling water, we can use the formula:

Power = (Mass flow rate) x (Gravity) x (Height)

Given:
Mass flow rate = 1.3 × 10^6 kg/s
Gravity = 9.81 m/s^2
Height = 49.8 m

Substituting these values into the formula, we get:

Power = (1.3 × 10^6 kg/s) x (9.81 m/s^2) x (49.8 m)

Now we can calculate the power:

Power = 1.3 × 10^6 kg/s x 9.81 m/s^2 x 49.8 m

To multiply these numbers, we have:
1.3 × 10^6 x 9.81 x 49.8

First, multiply 1.3 x 9.81 = 12.753

Then, multiply 12.753 x 49.8 = 634.674

Finally, we get:
Power = 634.674 x 10^6 W

Therefore, the power generated by the falling water is 634.674 x 10^6 W.

power=force*distance/time=massrate*g*distance