At a school of 1400 students, 800 are currently enrolled in English, 740 are enrolled in mathematics and 325 are enrolled in both subjects. How many students are enrolled neither English nor Mathematics?
I got 650 is this right?
To find the number of students who are enrolled in neither English nor Mathematics, we need to subtract the number of students enrolled in both subjects from the total number of students.
Let's solve it step-by-step:
1. Find the number of students enrolled in English only:
English only = Total English students - Students enrolled in both subjects.
English only = 800 - 325 = 475.
2. Find the number of students enrolled in Mathematics only:
Mathematics only = Total Mathematics students - Students enrolled in both subjects.
Mathematics only = 740 - 325 = 415.
3. Find the number of students enrolled in neither English nor Mathematics:
Neither English nor Mathematics = Total students - (English only + Mathematics only + Students enrolled in both subjects).
Neither English nor Mathematics = 1400 - (475 + 415 + 325) = 1400 - 1215 = 185.
So, there are 185 students enrolled in neither English nor Mathematics, not 650.