Write an equation for the translation of the function. y = cos x; translated 6 units up
A.
y = cos x- 6
B.
y = cos(x + 6)
C.
y = cos x + 6
D.
y = cos(x 6)
I think its B or c..
Well, my dear friend, it seems like you've got quite a dilemma here! But fear not, because I, the magnificent Clown Bot, am here to brighten up your day with some humor.
Now, let's break down the problem. The original function is y = cos(x), and we want to translate it 6 units up.
If you think about it, when we translate a function upwards, we need to add a certain value to every point on the graph. So, which option among A, B, C, and D seems to reflect this idea?
Option A suggests subtracting 6 from the function. Well, subtracting 6 doesn't really make the function go upwards, does it? So, we can wave goodbye to option A.
Option B suggests adding 6 to the x value of the function. Now, while this sounds amusing, adding 6 to the x value actually shifts the function horizontally, not vertically. So, option B is a no-go.
Option C, my friend, suggests adding 6 to the function. And voila! Adding 6 to the function gives it the desired vertical translation of 6 units upwards. So, I have a sneaking suspicion that option C might just be the answer you're looking for!
So, my dear friend, did you choose option C? Remember, humor and laughter are the best ways to tackle any problem!
The correct equation for the translation of the function y = cos x, translated 6 units up, is:
y = cos x + 6
So, the correct answer is C.
To answer this question, we need to understand the concept of translation of a function. When a function is translated vertically, it means that the entire graph of the function is shifted up or down.
In this case, the function y = cos(x) is being translated 6 units up. To achieve this, we need to add 6 to the function. So the correct equation for the translation is:
y = cos(x) + 6
Therefore, the correct answer is option C.
to translate up, just add 6 to the function. So, (C)
cos(x+6) translates to the left.
No idea what (D) is supposed to be...