P +HNO3 gives HPO3 + NO Balance the chemical equation by oxidation no. method
P+HNO3=HPO3+NO+H2O
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P+Hno3 gives HPo3 +no + H20
To balance the chemical equation using the oxidation number method, we need to determine the oxidation numbers of each element in the equation and then make sure they are balanced on both sides of the equation.
Let's start by assigning oxidation numbers to each element:
P: Let's assume that the oxidation number of P is x.
H: The oxidation number of hydrogen (H) is always +1 in compounds.
N: The oxidation number of nitrogen (N) in HNO3 is +5, since oxygen is more electronegative and each hydrogen is +1.
O: The oxidation number of oxygen (O) in HNO3 is -2, since it is more electronegative.
Now, let's write the equation with the assigned oxidation numbers:
P + HNO3 → HPO3 + NO
Since there is no charge specified for the reactants or products, we can assume they are neutral. Therefore, the sum of oxidation numbers on both sides should be zero.
Reactants:
P: x
H: +1
N: +5
O: -2 (-2 x 3 = -6 total)
Products:
H: +1
P: +x
O: -2 (-2 x 3 = -6 total)
N: +2 (since NO has a charge of +2, and there is only one nitrogen atom)
Now we can balance the equation by equalizing the total oxidation numbers on both sides. Since there is one P atom on the reactant side, we need one on the product side as well. This implies that the oxidation number of P is +5 on the product side.
We can write the balanced equation:
P + 4HNO3 → HPO3 + NO
By this method, the chemical equation is balanced, satisfying both mass conservation and charge neutrality.