Sam is setting up the basic design for a product line for chocolate
bars. The line needs to produce 200000 bars per eight hours shift and it run
continuously.The conveyor is 1m wide and each bar is 20mm wide and 60mm
long. if the length of line is 250m, at what average speed , khp , must it run
assuming the belt surface is covered with bars, then it makes sense to line them up 50 bars across (50*20=1000mm = 1m).
So, the 250m-log surface can hold 250/.06 = 4167 bars
Thus, the total surface of the belt can hold 4166*50 = 208,333 bars at once.
Thus only .96 belt-lengths per 8-hr shift is required.
.96*250m/8hr = 0.12 m/hr
I suspect that there are other considerations.
To find the average speed in kilometers per hour (kph) at which the conveyor must run, we first need to calculate the total distance traveled by the chocolate bars in 8 hours.
Step 1: Convert the length of the conveyor from meters to millimeters:
250 meters = 250 * 1000 = 250,000 millimeters
Step 2: Calculate the number of chocolate bars produced per hour:
200,000 bars / 8 hours = 25,000 bars per hour
Step 3: Calculate the distance traveled by a single chocolate bar in one hour:
20mm (width of bar) + 60mm (length of bar) = 80mm
80mm * 25,000 bars = 2,000,000 mm
Step 4: Calculate the distance traveled by a single chocolate bar in 8 hours:
2,000,000 mm * 8 = 16,000,000 mm
Step 5: Convert the distance to kilometers:
16,000,000 mm / 1,000,000 = 16 kilometers
So, the conveyor must run at an average speed of 16 kilometers per hour (kph) for the production line to produce 200,000 chocolate bars per eight-hour shift continuously.