Suppose the integral from 2 to 8 of g of x, dx equals 13, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of 2 plus the integral from 2 to 6 of g of x, dx.

16
18
8
32

It’s not 32(flvs)

To find the value of 2 plus the integral from 2 to 6 of g(x), dx, we need to evaluate both integrals separately and then add them together.

Given that the integral from 2 to 8 of g(x), dx equals 13 and the integral from 6 to 8 of g(x), dx equals -3, we can rewrite the integral we want to find as:

2 + ∫[2 to 6] g(x), dx

To solve this, we need to split the original integral into two parts:

(2 + ∫[2 to 8] g(x), dx) - ∫[6 to 8] g(x), dx

Now, substituting the given values, we get:

(2 + 13) - (-3)

Simplifying this expression, we have:

2 + 13 + 3 = 18

Therefore, the value of 2 plus the integral from 2 to 6 of g(x), dx is 18.