The world record for a human holding their breath is 11 minutes, but most people can only hold it for a few minutes. If a women holds her breath at the maximum lung capacity (4.2 L), calculate the final pressure in her lungs, if her body temperature is 37.0 C and the ambient air temperature in the room is 20.0 C and pressure is 1.08 atm.

4.2 / 310 = 4.2 / 293 = 1.02079 is this correct?

To calculate the final pressure in the woman's lungs, we need to use the ideal gas law equation, which is:

PV = nRT

Where:
P is the pressure
V is the volume
n is the number of moles of gas
R is the ideal gas constant
T is the temperature in Kelvin

First, we need to convert the temperatures from Celsius to Kelvin:
Body temperature (37.0 C) + 273.15 = 310.15 K
Ambient air temperature (20.0 C) + 273.15 = 293.15 K

Now, we can calculate the number of moles of gas:
n = volume / molar volume
molar volume at standard temperature and pressure (STP) is 22.4 L/mol

n = 4.2 L / 22.4 L/mol = 0.1875 mol

Next, we can calculate the final pressure in the woman's lungs:
P1V1 / T1 = P2V2 / T2

P1 = 1.08 atm (initial pressure)
V1 = 4.2 L (initial volume)
T1 = 293.15 K (initial temperature)
P2 = ? (final pressure)
V2 = 4.2 L (final volume)
T2 = 310.15 K (final temperature)

1.08 atm * 4.2 L / 293.15 K = P2 * 4.2 L / 310.15 K

Simplifying the equation:
P2 = (1.08 atm * 4.2 L * 310.15 K) / (293.15 K * 4.2 L)
P2 = 1.1477 atm

Therefore, the final pressure in the woman's lungs, if her body temperature is 37.0 C (310.15 K) and the ambient air temperature is 20.0 C (293.15 K), would be approximately 1.1477 atm.