Problem:
a^2-9 a^2-3a
----- * --------
a^2 a^2+a-12
Here Is What I Got:
(a+3)3a
-------
(a+4)
*Please Check It.I think I did it wrong though.. =[
I'm going to assume your problem is this:
(a^2-9)/a^2 * (a^2-3a)/(a^2+a-12)
Note: I'm using * to mean multiply.
If that is the problem, then you want to try to factor first, so you can reduce wherever you can.
Factoring:
(a+3)(a-3)/a^2 * a(a-3)/(a+4)(a-3)
Cancel out (a-3) in both the numerator and denominator of the second fraction to end up with this:
(a+3)(a-3)/a^2 * a/(a+4)
Multiplying:
a(a+3)(a-3)/a^2(a+4)
We can still reduce a/a^2 to end up with this:
(a+3)(a-3)/a(a+4)
And that's about as far as we can go on this one!
I hope this helps and is what you were asking for this problem.
It seems like there was a misunderstanding in how the problem was interpreted.
To simplify the expression (a^2-9)/(a^2) * (a^2-3a)/(a^2+a-12), we need to factor and cancel out common terms in the numerator and denominator of each fraction.
(a^2-9) can be factored as (a-3)(a+3).
(a^2-3a) cannot be further factored.
(a^2+a-12) can be factored as (a+4)(a-3).
Now, let's rewrite the expression:
[(a-3)(a+3)/(a^2)] * [(a^2-3a)/((a+4)(a-3))]
Next, we can cancel out the common factor (a-3) in both the numerator and denominator of the second fraction, and rewrite the expression again:
[(a-3)(a+3)/(a^2)] * [a/(a+4)]
Finally, since there are no more common factors in the numerator and denominator, we multiply the two fractions together:
(a-3)(a+3)(a)/(a^2)(a+4)
The simplified expression is:
(a-3)(a+3)(a)/(a^2)(a+4)
I hope this clear explanation helps! Let me know if you have any further questions.