# integrate

how do i integrate

2u du /u-2+2u^2

so i used subsitution rule?
or can i used integration by parts and how? thanks in adnvace

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1. Is all of u -2 +2u^2
a denominator?

That is (2u-1)(u+1)

So you would be integrating
2u/[(2u-1)(u+1)]

The method of partial fractions can be used.

See
http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html

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posted by drwls

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