in a rational number... nemerator is 3 less than the denominator. if 3 is added to the numerator.. fraction becomes 1. find the fraction??

3/6

Yourself

To solve this problem, let's represent the numerator as "n" and the denominator as "d."

According to the given information, the numerator (n) is 3 less than the denominator (d). So we can write the equation: n = d - 3

We are also told that if 3 is added to the numerator, the fraction becomes 1. Therefore, we can write another equation: (n + 3) / d = 1

Now we have a system of two equations:

Equation 1: n = d - 3
Equation 2: (n + 3) / d = 1

To find the fraction, we need to solve this system of equations.

Let's substitute the value of n from Equation 1 into Equation 2:

((d - 3) + 3) / d = 1
(d - 3 + 3) / d = 1
d/d = 1

By canceling out the d's on the left side, we get:

1 = 1

This equation is always true, which means that the value of d can be any number. Since d is the denominator, we can choose any positive integer value for d.

Let's assume d = 4.

Then, we can substitute this value of d into Equation 1 to find the numerator:

n = d - 3
n = 4 - 3
n = 1

So, when the numerator (n) is 1 and the denominator (d) is 4, the fraction is 1/4.

Therefore, the fraction is 1/4.