At what height above the ground must a body of mass 10kg besituated in order to have potentral energy possed by another body of mass 10kg maining with velocity of 10ms

m g h = 1/2 m v²

h = v² / (2 g)

To determine the height at which a body of mass 10kg must be situated in order to have potential energy equal to the kinetic energy possessed by another body of mass 10kg moving with a velocity of 10m/s, we can use the principles of conservation of mechanical energy.

The potential energy of an object at a certain height is given by the formula:

Ep = mgh

Where:
Ep is the potential energy
m is the mass of the object
g is the acceleration due to gravity
h is the height

The kinetic energy of an object is given by the formula:

Ek = 0.5 * m * v^2

Where:
Ek is the kinetic energy
m is the mass of the object
v is the velocity

Based on the conservation of mechanical energy, we can equate these two energies:

Ep = Ek

mgh = 0.5 * m * v^2

Since the mass of both objects is given as 10kg, we can cancel out the "m" terms:

10 * g * h = 0.5 * 10 * 10^2

Simplifying the equation further:

10 * g * h = 0.5 * 10 * 100

10 * g * h = 0.5 * 1000

10 * g * h = 500

Dividing both sides by 10 * g:

h = 500 / (10 * g)

h = 500 / (10 * 9.8)

h ≈ 5.1 meters

Therefore, the body of mass 10kg must be situated at a height of approximately 5.1 meters above the ground to have potential energy equal to the kinetic energy possessed by the other body of the same mass moving at a velocity of 10m/s.