A detailed science laboratory setup demonstrating the burning of carbon in air. The scene could include safety gear like gloves and goggles, a Bunsen burner igniting a piece of carbon, and two transparent glass containers - one having air and the other collecting CO2 gas. Also, include a measuring scale showing the accurate measuring of 6 grams of carbon. The overall ambiance of the image should be appealing and educational. It is important that the image contains no text.

You burn 6 grams of carbon in plenty of air:

C ( s) + O2 ( g) = CO2 ( g)
a What volume of gas will form (at rtp)?
b What volume of oxygen will be used up?

a) mass=6g Ar=12

Mr=12g/mol
n=m÷Mr
n=6g÷12g/mol
n=0.5 mol


V=n*Vm =0.5molx24dm(cubed)/mol
=12dm(cubed)

Go clean the dishes

a) 12grams= 1 mole

6 grams= 0.5 mole
0.5 ×24= 12dm³
Answer=12dm³

Hi what is a and what is b I don't know.

b) From the balanced equation, we can see that for every 1 mole of carbon burned, 1 mole of oxygen is required. Therefore, since we have 0.5 moles of carbon, we also need 0.5 moles of oxygen.

Using the ideal gas law, we can calculate the volume of oxygen used:

PV = nRT

Assuming constant temperature and pressure (rtp):

V = nRT/P

V = (0.5 mol)(8.31 J/mol·K)(273 K)/(101.3 kPa)

V = 10.9 L or 10900 mL

Therefore, 10.9 L or 10900 mL of oxygen will be used up.

rfvwsvsdjvedrbfbdfboidfonbdnld nln ldfnbnldfcnbnbfnfndnfwef55883-86686-386-68

Please Label which one is A and B

57

E=MC SQUARE

THE E=MC SQUARE COMES IN DR.STONE ANIME.BUT 12 DM3 IS THERE BECAUSE THERE IS ONLY 6 G OF CARBON . 6 G OF CARBON HAS THE VOLUME OF 12DM3 WHICH IS 24DM3 DIVIDED BY TWO.SO DONT WORRY IF YOU HAVE ANY DOUBT YOU CAN CALL ME.9976852351

how many moles involved?

1 mole is 22.4L at stp