7.) How many moles of fluroine are required to react with 12 g of sodium iodide?
I already balanced it but am confused to go from here
F2 + 2 NAi ---- 2 NaF + I2
12 g NaI + 2 mol NAI/149.89 gNAi * 1 mol NAF/1 mol NAi * 1 mol F2 / 2 mol NaF
1.) how many grams of magnesium are needed to react with 1.25 mol of hydrochloric acid?
2.) Carbon and sulfur dioxide react to form carbon disulfide and carbon monoxide. How many moles of carbon disulfide would be expected if 7.09 g of carbon monoxide were produced
Here is what I did but idk if it is correct.
HELP?
7.09 g CO * 1mol CO/28.01 gCO * 1 molC/ 4 mol CO * 1 mol CS2/5 mol C=
3.) Calculate the mass of sodium hydroxide required to completely neutralize 21.7 g of sulfuric acid
2 NaOH + H2SO4 ---- Na2SO4 + 2 H2O
...
21.7 g H2SO4 * 1mol H2SO4/98.079 g H2SO4 * 2 mol NaOH/1 mol H2SO4=
Most of these stoichiometry problems are worked the same way.
Here is a step by step procedure.
7.) How many moles of fluorine are required to react with 12 g of sodium iodide?
I already balanced it but am confused to go from here
F2 + 2 NAi ---- 2 NaF + I2
12 g NaI + 2 mol NAI/149.89 gNAi * 1 mol NAF/1 mol NAi * 1 mol F2 / 2 mol NaF
1. Write and balanced the equation. Except for a couple of typos you've done that.
F2 + 2NaI ---- 2 NaF + I2
2. Convert what you have into mols. mols NaI = grams NaI/molar mass NaI= approx 0.08 but that's an estimate.
3. Now convert mols NaI to mols F2 using the coefficients in the balanced equation. That's
approx 0.08 x (1 mol F2/2 mols NaI) = approx 0.08 x 1/2 = ?
Thankyou thankyou so much. Making it harder than it should be.
To solve each of these stoichiometry problems, you will need to use the balanced chemical equations and the concept of moles.
8.) How many grams of magnesium are needed to react with 1.25 mol of hydrochloric acid?
Given the balanced equation: Mg + 2 HCl -> MgCl2 + H2
Step 1: Identify the molar ratio between magnesium and hydrochloric acid from the balanced equation. In this case, 1 mole of Mg reacts with 2 moles of HCl.
Step 2: Set up a conversion factor to calculate the mass of magnesium. Use the molar mass of magnesium, which is 24.31 g/mol.
1.25 mol HCl * 1 mol Mg / 2 mol HCl * 24.31 g Mg / 1 mol Mg = 15.19 g Mg
Therefore, you would need 15.19 grams of magnesium to react with 1.25 moles of hydrochloric acid.
9.) Carbon and sulfur dioxide react to form carbon disulfide and carbon monoxide. How many moles of carbon disulfide would be expected if 7.09 g of carbon monoxide were produced?
Given the balanced equation: C + 2 SO2 -> CS2 + CO2
Step 1: Identify the molar ratio between carbon disulfide and carbon monoxide from the balanced equation. In this case, 1 mole of CO reacts to form 1 mole of CS2.
Step 2: Set up a conversion factor to calculate the moles of carbon disulfide. Use the molar mass of carbon monoxide, which is 28.01 g/mol.
7.09 g CO * 1 mol CO / 28.01 g CO * 1 mol CS2 / 1 mol CO = 0.252 mol CS2
Therefore, you would expect to produce 0.252 moles of carbon disulfide if 7.09 g of carbon monoxide were produced.
10.) Calculate the mass of sodium hydroxide required to completely neutralize 21.7 g of sulfuric acid.
Given the balanced equation: 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O
Step 1: Identify the molar ratio between sodium hydroxide and sulfuric acid from the balanced equation. In this case, 2 moles of NaOH react with 1 mole of H2SO4.
Step 2: Set up a conversion factor to calculate the mass of sodium hydroxide. Use the molar mass of sulfuric acid, which is 98.079 g/mol.
21.7 g H2SO4 * 1 mol H2SO4 / 98.079 g H2SO4 * 2 mol NaOH / 1 mol H2SO4 = 0.443 mol NaOH
Step 3: Finally, calculate the mass of sodium hydroxide by multiplying the number of moles by its molar mass, which is 39.997 g/mol.
0.443 mol NaOH * 39.997 g NaOH / 1 mol NaOH = 17.72 g NaOH
Therefore, you would need 17.72 grams of sodium hydroxide to completely neutralize 21.7 g of sulfuric acid.