the sum of two numbers is 27. one number is 3 more than the other number. write and solve a system of equations to find the two numbers.

i understand the first equation but i don't know the other one.

Bakvasa

Can I?

NUT IN BUTT

To write a system of equations to solve this problem, we need to define two unknowns. Let's say the two numbers are represented by the variables x and y.

We know that the sum of two numbers is 27, so our first equation is:
x + y = 27

The problem also states that one of the numbers is 3 more than the other number. This can be represented by the equation:
x = y + 3

Now we have a system of equations:
x + y = 27
x = y + 3

To solve this system, we can use the method of substitution. We solve one equation in terms of one variable and then substitute it into the other equation.

From the second equation, we can solve for x in terms of y:
x = y + 3

Now substitute this expression into the first equation:
(y + 3) + y = 27

Simplifying, we get:
2y + 3 = 27

To isolate y, we subtract 3 from both sides:
2y = 24

Finally, divide both sides by 2:
y = 12

Now that we have found the value of y, we can substitute it back into the equation x = y + 3 to find x:
x = 12 + 3
x = 15

So, the two numbers are 15 and 12.

The logical solution is to take away 3 from 27 and divide by two to give the smaller number. Then add 3 to get the bigger number. Check by adding the two results to see if they add up to 27.

If you have to use system of 2 linear equations, then
let x=smaller number
y=larger number
y-x=3...............(1)
x+y=27..............(2)
and solve for x and y. You should get the same results as the procedure mentioned at the beginning.