At summer camp 20% of the students come from out of state. Megan wants to simulate cabins of 8 campers. She generates random digits from 0 to 9 and lets the digits 0 and 1 represent a camper from out of state.
The table:
69531217; 89542756; 89001254; 01346895; 12468503
20312346; 79564328; 59868542; 75891003; 56103249
58630126; 57498510; 76134860; 52974168; 03164985
03289642; 68533236; 94210145; 70215789; 32605254
What is the experimental probability that in a cabin of 8 campers, at least 2 are from out of state?
A. 7/20
B. 13/20
C. 7/10
D. 4/5
I don’t know if it is B or D… any thoughts?
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In fact, we are the ones to ask you for any thoughts!
To find the experimental probability that at least 2 campers are from out of state in a cabin of 8 campers, we need to analyze the given table that represents random digits generated by Megan.
Let's count the number of times there are at least 2 out-of-state campers in each row:
- In the first row, there are 2 out-of-state campers.
- In the second row, there are 2 out-of-state campers.
- In the third row, there are 2 out-of-state campers.
- In the fourth row, there are 3 out-of-state campers.
Out of the 4 rows, 3 of them have at least 2 out-of-state campers.
Since each row represents a cabin of 8 campers and there are 4 rows in total, this means we have a total of 4 cabins of 8 campers.
Therefore, the experimental probability that in a cabin of 8 campers, at least 2 are from out of state is 3 out of 4, or 3/4.
However, none of the given answer choices matches this probability. Therefore, it seems there may be an error in the answer choices or the data provided. Please verify the question or answer choices again to narrow down the possibilities.