can you please help me solve this quadadratic equasionby factoring :
x^2-8x+16 would this be the right way
8x^3+16 to start
OH NO, you cannot add unlike terms
x^2 - 8x + 16
=(x-4)(x-4)
check it by expanding
BTW, you did not have an "equation".
did you have x^2 - 8x + 16 = 0 ?
then (x-4)(x-4)=0
x = -4
The factors of x^2 - 8x + 16 are (x-4)(x-4)
You did not write an equation.
If you had written x^2 -8x + 16 = 0, which IS an equation, the answer would be x = 4. That would be the only answer, since both factors are zero when x = 4.
I obviously meant x = 4 (not -4)
(that "oldtimers" syndrome hitting again)
To solve the quadratic equation by factoring, you need to find two factors of the constant term (16) that add up to the coefficient of the linear term (-8x). In this case, the constant term is 16.
To factor the quadratic equation `x^2-8x+16`, you need to find two numbers whose product is 16 and whose sum is -8.
Let's list the possible factor pairs of 16:
1 * 16 = 16
2 * 8 = 16
4 * 4 = 16
Among these pairs, the pair that adds up to -8 is 4 * 4 = 16.
So, the factored form of the quadratic equation `x^2-8x+16` is (x-4)(x-4).
To check if this is correct, you can expand the factored form by multiplying it out:
(x-4)(x-4) = x^2 - 8x + 16
As you can see, the factored form expands back to the original quadratic equation.
Therefore, the solution to the quadratic equation `x^2-8x+16` is x = 4.