If a ball that is freely falling has attained a velocity of 19.6 m/s after two seconds, what is its velocity five seconds later?

Nope. Sorry J.

7*9.8=68.6

@Chanz, oops my bad, you are correct.

Vf-19.6 m/s= (9.8 m/s/s)(5 s)
Vf-19.6 m/s = 49 m/s
Vf= 68.6 m/s

nope, you forgot acceleration (a)

a=vf (final velocity) - vi (initial velocity) divided by t (time)
the acceleration of a free falling body is 9.8 m/s/s due to the force of gravity.
9.8 m/s/s=vf-19.6m/s / 7s
if you multiply both sides by 7, you get
68.6 m/s/s=vf-19.6 m/s
then you add 19.6 to both sides and you get
88.2 m/s/s= vf
so the final velocity (the answer) is equal to 88.2 m/s/s

correct me if I'm wrong but I think that's how you do it

forgot that last calculation :)

wait so i did 9.8 times 5 and got 49, is that the final answer? and how did you guys get 68.6 and what does that number mean?

To find the velocity of the ball five seconds later, we need to use the formula for velocity in free fall.

The formula for velocity in free fall is given by:

v = u + gt

where:
v = final velocity
u = initial velocity
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time

In this case, after two seconds, the ball has attained a velocity of 19.6 m/s. So we can substitute these values into the formula:

19.6 = u + (9.8 * 2)

Now, we can solve for the initial velocity (u):

u = 19.6 - (9.8 * 2)
u = 19.6 - 19.6
u = 0 m/s

Since the ball is freely falling, the initial velocity u is 0 m/s. Now we can substitute the values into the formula to find the final velocity after five seconds:

v = u + gt
v = 0 + (9.8 * 5)
v = 0 + 49
v = 49 m/s

Therefore, the velocity of the ball five seconds later is 49 m/s.

t=19.6/2

v=5 * 9.8
=49 m/s