A piece of wire is 60 inches long. The wire needs too be bent into two peices. The prices are both bent in a square. If the ratio of the length or the pieces are 3:2. What is the ration for the smaller square to the nuggets square?

Sorry I meant bigger

To solve this problem, we need to understand the given information and set up the equations.

Let's assume the length of the smaller piece of wire is 3x inches and the length of the larger piece is 2x inches.

According to the given ratio, the sum of these two lengths should be equal to the total length of the wire, which is 60 inches:

3x + 2x = 60
5x = 60
x = 12

Now that we know the value of x, we can calculate the lengths of the two pieces:

Length of the smaller piece = 3x = 3 * 12 = 36 inches
Length of the larger piece = 2x = 2 * 12 = 24 inches

From these lengths, we can calculate the perimeters of the two squares.

Perimeter of the smaller square = 4 * (side length of smaller square) = 4 * 36 = 144 inches
Perimeter of the larger square = 4 * (side length of larger square) = 4 * 24 = 96 inches

Now, let's find the ratio of the smaller square to the larger square.

Ratio = (Perimeter of smaller square) / (Perimeter of larger square)
= 144 / 96
= 3 / 2

Therefore, the ratio of the smaller square to the larger square is 3:2.