How many grams of salt can be produced from five grams of sodium and unlimited bromine?
Is this 39.75 g NaBr?
5 grams of Na is 5/23 = .2174 mols
so we get .2174 mols of NaBr
NaBr = 23 + 80 = 103 grams/mol
.2174 * 103 = 22.4 grams
Is this 39.75 g NaBr?
so we get .2174 mols of NaBr
NaBr = 23 + 80 = 103 grams/mol
.2174 * 103 = 22.4 grams