The rocketdriven sled Sonic Wind No. 2, used for investigating the physiological effects of large accelerations, runs on a straight, level track that is 1080 long. Starting from rest, it can reach a speed of 1610 in 1.80 .
what is the distance covered in 1.80s?
You neglected to say what your length and speed dimensions are. That is a serious error in physics. They are probably either feet or meters.
If it reaches a speed of 1610 (m/s?)in 1.80 s, its average speed during that interval is 805 m/s. Multiply 805 m/s by the time interval (1.80 s) for the distance traveled. Make sure you include the length dimension units.
I come up with a distance covered (while reaching top speed)that exceeds the track length. Are you sure you copied the problem coreectly?
To find the distance covered in 1.80 seconds, we can use the formula for distance:
distance = initial velocity * time + (1/2) * acceleration * time^2
However, we are not given the acceleration directly, but we are given the final velocity and the time to reach that velocity. We can use the equation for velocity:
final velocity = initial velocity + acceleration * time
Rearranging the equation, we get:
acceleration = (final velocity - initial velocity) / time
Substituting the given values:
acceleration = (1610 m/s - 0 m/s) / 1.80 s
acceleration = 894.44 m/s^2
Now that we have calculated the acceleration, we can use it to find the distance covered in 1.80 seconds. Substituting the values into the distance formula:
distance = 0 * 1.80 + (1/2) * 894.44 * (1.80)^2
distance = 0 + (0.5) * 894.44 * 3.24
distance = 1452.13 meters
Therefore, the distance covered in 1.80 seconds is 1452.13 meters.