# Exponential Growth and Decay

1. Identify the initial amount a and the growth factor b in the exponential function.

g(x)=14*2^x
a)a=14, b=x
b)a=14, b=2 <<<<
c)a=28, b=1
d)a=28, b=x

2. Identify the initial amount a and the growth factor b in the exponential function.

f(t)=1.4^t
a)a=1, b=0.4
b)a=1.4, b=0<<<<
c)a=1.4, b=t
d)a=1, b=1.4

3.Find the balance in the account after a given period.
\$4000 principal earning 6% compounded annually, after 5 years.

a)\$6,726.28
b)\$5,352.90<<<<
c)\$5,395.40
d)\$7,716.74

6.Identify the initial amount a and the growth factor b in the exponential function.

y=5*0.5^x

a)a=5, b=x
b)a=0.5, b=5
c)a=5, b=0.5<<<<<
d)a=0.5, b=x

11. State whether the equation represents exponential growth, exponential decay or neither.

y=5.8(3/7)^x
a) Exponential growth
b) Exponential decay<<<<<
c) Neither

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1. #1 ok
#2 initial amount is 1.4^0=1
#3 ok
#6 ok
#7 ok

I'm surprised you blew it on #2; the others indicate good understanding.

What do you think b=0 would indicate?

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2. As soon as I posted this I realized I put the wrong one :/
Thank you for checking my work!

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3. 1B 2D 3B 4B 5A 6C 7B 8B 9B 10D 11B 12C 100% Correct

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4. zolita is right

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5. Zolita is 100% right if you are in connections.
1. B.
2. D.
3. B.
4. B.
5. A.
6. C.
7. B.
8. B.
9. B.
10. D.
11. B.
12. C.

These answers are all correct in Pre-AP (and possibly on-level too) Algebra in connections academy.

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6. i can confirm that zolita and answer king are correct!

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7. Oui, AnswerKing and Zolita are correct!

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8. yep! 12/12 100%!

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2. 👎

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10. OMG ZOLITA IS SOOOO CORRECT I GOT 12/12 DEFINETLT SUPER GREATFUL!

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11. Thank you so much Zolitaaaaa

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12. Thanksss Zolita 100%:)

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13. 1. B.
2. D.
3. B.
4. B.
5. A.
6. C.
7. B.
8. B.
9. B.
10. D.
11. B.
12. C.
U3L7 Exponential Growth and Decay

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14. Thanksss Zolita!!! :)

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15. Thanks Zolita!

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16. Lol still right 2019 thanks Zolita

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17. She is still right

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18. Thankk youuuuuuuuuuu

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19. Thanks zoilta

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20. Thanks DingDong and Zolta

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21. @Zolita is correct!

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22. yup zolita is =>

that was right get it?

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23. Zolita is still correct ! 12/12 - Jan. 2020 !^^ (Connections Academy.)

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24. 1. B
2. D
3. B
4. B
5. A
6. C
7. B
8. B
9. B
10. D
11. B
12. C

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25. Trust that^^

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26. Thank you Zolita so Much I got 100%☺

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27. I know your thinking that, there's too many B's in the questions but zolita is correct, I was taking one for the boi'zz

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28. Zolita is still correct!

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29. my test has 15... what?

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30. Be careful of these lists of answers without explanations. Sometimes kids deliberately post wrong answers. Sometimes teachers and/or test publishers mix the questions and answer choices up. Sometimes they change them completely!

Be aware!

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👤
Writeacher
31. THANK YOU ZOLITA

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32. Muy Bien, Zolita.
Usted es 100 días más inteligente y 100% correcto.
:)
Actually, I had got these answers correct, but I came here to double check my work. Zolita is 100% correct. I want to thank her for her help, since, as you know, there are some people who -- just -- do not -- HELP.
You do not find true friends easily. So, thx again!
Correcto as of 2021:):):):):)

1. B
2. D
3. B
4. B
5. A
6. C
7. B
8. B
9. B
10. D
11. B
12. C

Gracias de nuevo, Zolita!

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33. The above is correct for Algebra 1 B Unit 2 Lesson 7 Connexus:

1. B
2. D
3. B
4. B
5. A
6. C
7. B
8. B
9. B
10. D
11. B
12. C

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34. The people above are 100% correct I just did it . And got a 100% 😊

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35. Zolita is still correct. I got a 100%. These are the answers.
1. B
2. D
3. B
4. B
5. A
6. C
7. B
8. B
9. B
10. D
11. B
12. C

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36. Me when the when the

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37. 1B 2D 3B 4B 5A 6C 7B 8B 9B 10D 11B 12C 100% Correct

Zolita
Feb 22, 2017
this is right for OCA 2021

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38. zolita is right ignore everyone else lewl

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39. ZOLITA IS STILL GREAT

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40. No it's
1.A
2.C
3.B
4.C
5.A
6.D
7.A
8.C
9.A
10.A
11.
12.B

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41. thanks so much zolita and answerking!!!

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42. 01001001 00100000 01101100 01101001 01101011 01100101 00100000 01110100 01110010 01100001 01101001 01101110 01110011 00101100 00100000 01100100 01101111 00100000 01111001 01101111 01110101 00100000 01101100 01101001 01101011 01100101 00100000 01110100 01110010 01100001 01101001 01101110 01110011 00111111

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