i am having problems solving this question can you please help?
b[(12c-3a)2-10=
a=2, b=3, c=4
To solve the equation b[(12c - 3a)^2 - 10], you need to substitute the given values for a, b, and c.
Given a = 2, b = 3, and c = 4, we can plug these values into the equation:
b[(12c - 3a)^2 - 10]
= 3[(12(4) - 3(2))^2 - 10]
= 3[(48 - 6)^2 - 10]
= 3[42^2 - 10]
= 3[1764 - 10]
= 3[1754]
= 5262.
Therefore, when you substitute a = 2, b = 3, and c = 4 into the equation b[(12c - 3a)^2 - 10], the result is 5262.
Of course! I'd be happy to help you solve the question. Let's break it down step by step.
The given equation is: b[(12c - 3a)2 - 10]
To solve it, we can substitute the values of a, b, and c into the equation. Given a = 2, b = 3, and c = 4, we can substitute these values into the equation and then simplify.
1. Substitute a = 2, b = 3, and c = 4 into the equation:
b[(12c - 3a)2 - 10] = 3[(12 * 4 - 3 * 2)2 - 10]
2. Simplify the expression inside the square brackets:
[(12 * 4 - 3 * 2)2 - 10] = [(48 - 6)2 - 10]
3. Continue simplifying:
[(48 - 6)2 - 10] = [42^2 - 10] = [1764 - 10] = 1754
4. Substitute the simplified expression back into the equation:
b[(12c - 3a)2 - 10] = 3 * 1754 = 5262
Therefore, b[(12c - 3a)2 - 10] equals 5262 for the given values of a = 2, b = 3, and c = 4.
I hope this explanation helps you understand how to solve the question. Let me know if you have any further questions!